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Gravitational Potential Energy Calculator (PE = mgh)

Potential energy from mass and height in kg or lb and m or ft, with the speed a drop from that height would give.

Inputs

Gravitational PE
196.13 J

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What each Gravitational Potential Energy input means

Mass
The object's mass, in kilograms or pounds.
Mass unit
kg or lb; pounds are converted at 0.45359237 kg.
Height above the reference
How far above your chosen reference level it is — the floor, the ground, the bottom of the drop. Negative if it is below that level.
Height unit
Metres or feet; feet are converted at exactly 0.3048 m.
Gravity (g)
Gravitational acceleration, 9.80665 m/s² by default. Use 1.62 for the Moon or 3.72 for Mars.

Gravitational Potential Energy formula

PE = m × g × h (m in kg, g in m/s², h in m above your chosen reference; PE in joules) · speed if released, no air: v = √(2gh)

PEg=mghv=2ghPE_g = m g h \qquad v = \sqrt{2 g h}

Gravitational potential energy is the work it took to lift something against gravity, stored ready to come back out: the weight (mass × g) times the height lifted. It is always measured from a reference level you choose — the floor, the ground, sea level — so only differences in height carry meaning, and a height below the reference gives a negative value, which is fine. Pounds and feet are converted to kilograms and metres first, since the formula wants SI, and the working shows the conversion. If the object is released, all of that energy becomes kinetic energy on the way down (ignoring air), which is why the page also shows √(2gh), the speed at the bottom — the same figure the free-fall calculator reaches from the kinematics.

Gravitational Potential Energy worked example

A 2 kg mass lifted 10 m: 2 × 9.80665 × 10 = 196.1 J. Dropped from there it would reach √(2 × 9.80665 × 10) = 14.0 m/s just before landing, with 196.1 J of kinetic energy. Ten pounds lifted 20 feet is 4.54 kg × 9.80665 × 6.096 m = 271.2 J.

More Gravitational Potential Energy examples

A 60 kg person at the top of a 3 m ladder: 60 × 9.80665 × 3 = 1,765.2 J above the floor. Falling from there, they would land at 7.67 m/s, about 28 km/h.

Where the Gravitational Potential Energy calculator can give the wrong answer

  • The reference level is yours to choose, and the answer changes with it. A book on a table has 20 J relative to the table's surface and much more relative to the floor; both are correct, and only the difference between two positions is physically meaningful.
  • mgh assumes g is constant, which holds near the Earth's surface. For heights of hundreds of kilometres — satellites — gravity weakens with distance and the formula −GMm/r replaces it.
  • The drop speed shown ignores air resistance. A dense object from a few metres matches it closely; a feather or a person from a height does not, because drag takes energy out of the fall.
  • Pounds are converted as mass (0.45359237 kg per lb). Feet are 0.3048 m exactly.
  • This is gravitational potential energy only. Springs store elastic potential energy, ½kx²; charges store electrical potential energy; neither is on this page.

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Gravitational Potential Energy reference table

Per kilogram: the potential energy at a height, and the speed of a drop from it
HeightPotential energy of 1 kgSpeed at the bottom (no air)
1 m9.81 J4.43 m/s (15.9 km/h)
2 m19.61 J6.26 m/s (22.5 km/h)
5 m49.03 J9.9 m/s (35.7 km/h)
10 m98.07 J14 m/s (50.4 km/h)
20 m196.13 J19.81 m/s (71.3 km/h)
50 m490.33 J31.32 m/s (112.7 km/h)
100 m980.67 J44.29 m/s (159.4 km/h)
Source: Arithmetic: PE = mgh and v = √(2gh) with g = 9.80665 m/s² (OpenStax College Physics 2e, §7.3); multiply the energy column by the mass

Gravitational Potential Energy FAQ

Multiply the mass in kilograms by 9.81 m/s² by the height in metres: PE = mgh. A 60 kg person at the top of a 3 m ladder has 60 × 9.81 × 3 ≈ 1,766 J. In pounds and feet, convert first (0.4536 kg per lb, 0.3048 m per ft) — the page does it for you.